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Q. The initial nucleus of uranium series is $_{92}U^{238}$ and the final nucleus is $_{82}Pb^{206}$. When uranium decays to lead how many $\alpha$ and $\beta$ particles are produced ?

Atoms

Solution:

No. of $\alpha$-particles : $\frac{238 - 206}{4} = \frac{32}{4} = 8$ and No. of $\beta$--particles : 82 - (92 - 8 $\times$ 2) = 6