The increasing order of energies of various molecular orbitals of N2 is given below: σ 1s

Question

The increasing order of energies of various molecular orbitals of N2 is given below: σ 1s < σ* 1s <σ 2 s <σ* 2 s < π 2 px = π 2 p y < σ 2 pz < π* 2px = π* 2py < σ* 2pz The above sequence is not true for the molecule (A) C2 (B) B2 (C) O2 (D) Be2

Tardigrade Admin · Accepted Answer

For all elements which have atomic number more than 7 (beyond nitrogen) the energy of σ 2pz is lower than π 2px and π 2py -orbitals.

Q. The increasing order of energies of various molecular orbitals of $N_{2}$ is given below:
$σ 1 s < σ^{} 1 s < σ 2 s < σ^{} 2 s < π 2 p_{x}$
$= π 2 p_{y} < σ 2 p_{z} < π^{} 2 p_{x} = π^{} 2 p_{y} < σ^{*} 2 p_{z}$
The above sequence is not true for the molecule

$C_{2}$

$B_{2}$

$O_{2}$

$B e_{2}$

For all elements which have atomic number more than $7$ (beyond nitrogen) the energy of $σ 2 p_{z}$ is lower than $π 2 p_{x}$ and $π 2 p_{y}$ -orbitals.

Q. The increasing order of energies of various molecular orbitals of N2​ is given below: σ1s<σ∗1s<σ2s<σ∗2s<π2px​ =π2py​<σ2pz​<π∗2px​=π∗2py​<σ∗2pz​ The above sequence is not true for the molecule

C2​

B2​

O2​

Be2​