Question

The hybridization of central metal ion in $K_2[Ni(CN{)}_4]and{K}_2[NiC{l}_4]$ are respectively

• A. $ds{p}^2,s{p}^3$
• B. $s{p}^3,s{p}^3$
• C. $ds{p}^2,ds{p}^2$
• D. $s{p}^3,s{p}^3{d}^2$
• E. $s{p}^3{d}^2,d^{2}s{p}^3$

Answer 1

Answer: (A)

${\left[NiC{l}_4\right]}^{2-}$
$Ni$ is in $+2$ oxidation state.
$N{i}^{2+}-[Ar]3d^8$
Hybridization involved is $s{p}^3$ as participating orbitas are $4s$ and $4p$.
${\left[NiC{N}_4\right]}^{2-}$
Ni is in $+2$ oxidation state.
$N{i}^{2+}-[Ar]3d^8$
$C{N}^{-}$is a strong field ligand. It causes the pairing of the $3d$ electrons.
Hybridization involved is $ds{p}^2$ as participating orbitas are $3d,4s$ and $4p$.