Question

The hybridization of central metal ion in $K_2[Ni(CN)_4]\, and\, K_2[NiCl_4]$ are respectively

• A. $dsp^{2} , sp^{3}$
• B. $sp^{3} , sp^{3}$
• C. $dsp^{2} , dsp^{2}$
• D. $sp^{3} , sp^{3}d^{2}$
• E. $sp^{3}d^{2} , d^{2}sp^{3}$

Answer 1

Answer: (A)

$\left[ NiCl _{4}\right]^{2-}$
$Ni$ is in $+2$ oxidation state.
$Ni ^{2+}-[ Ar ] 3 d ^{8}$
Hybridization involved is $sp ^{3}$ as participating orbitas are $4 s$ and $4 p$.
$\left[ NiCN _{4}\right]^{2-}$
Ni is in $+2$ oxidation state.
$Ni ^{2+}-[ Ar ] 3 d ^{8}$
$CN ^{-}$is a strong field ligand. It causes the pairing of the $3 d$ electrons.
Hybridization involved is $dsp ^{2}$ as participating orbitas are $3 d , 4 s$ and $4 p$.