The hybridisation of sulphur in sulphur dioxide is

Question

The hybridisation of sulphur in sulphur dioxide is (A) sp (B) sp3 (C) sp2 (D) dsp2

Tardigrade Admin · Accepted Answer

In SO2, the Lewis-dot structure is Electron pairs at S = 2 (σbonds) + 1 (lone-pair) = 3 sp2 hybridised. NOTE π-bonded electrons are not present in hybrid orbitals, therefore not counted in electron pairs. Rather π bonds are formed by lateral overlapping of pure p-orbitals.

Q. The hybridisation of sulphur in sulphur dioxide is

sp

$s p^{3}$

$s p^{2}$

$d s p^{2}$

In $S O_{2}$ , the Lewis-dot structure is
Electron pairs at S = 2 ( $σ$ bonds) + 1 (lone-pair) = 3
$s p^{2}$ hybridised.
NOTE
$π$ -bonded electrons are not present in hybrid orbitals, therefore not counted in electron pairs. Rather $π$ bonds are formed by lateral overlapping of pure p-orbitals.

Q. The hybridisation of sulphur in sulphur dioxide is

sp

sp3

sp2

dsp2

In SO2​, the Lewis-dot structure is Electron pairs at S = 2 (σbonds) + 1 (lone-pair) = 3 sp2 hybridised. NOTE π-bonded electrons are not present in hybrid orbitals, therefore not counted in electron pairs. Rather π bonds are formed by lateral overlapping of pure p-orbitals.

$s p^{3}$

$s p^{2}$

$d s p^{2}$

In $S O_{2}$ , the Lewis-dot structure is
Electron pairs at S = 2 ( $σ$ bonds) + 1 (lone-pair) = 3
$s p^{2}$ hybridised.
NOTE
$π$ -bonded electrons are not present in hybrid orbitals, therefore not counted in electron pairs. Rather $π$ bonds are formed by lateral overlapping of pure p-orbitals.