The homologue of ethyne is

Question

The homologue of ethyne is (A)  C2H4  (B)  C3H6  (C)  C3H3  (D)  C3H4

Tardigrade Admin · Accepted Answer

The successive members of a homologous series differ by aCH2 group or by 12+2× 1=14 mass unit. Hence, the homologue of HC≡ CH (ethyne, C2H2) is CH3-C≡ CH (propyne, C3H4 ).

Q. The homologue of ethyne is

$C_{2} H_{4}$

$C_{3} H_{6}$

$C_{3} H_{3}$

$C_{3} H_{4}$

The successive members of a homologous series differ by $a C H_{2}$ group or by $12 + 2 \times 1 = 14$ mass unit. Hence, the homologue of $H C \equiv C H$ (ethyne, $C_{2} H_{2})$ is $C H_{3} - C \equiv C H$ (propyne, $C_{3} H_{4}$ ).

Q. The homologue of ethyne is

C2​H4​

C3​H6​

C3​H3​

C3​H4​

The successive members of a homologous series differ by aCH2​ group or by 12+2×1=14 mass unit. Hence, the homologue of HC≡CH (ethyne, C2​H2​) is CH3​−C≡CH (propyne, C3​H4​ ).

$C_{2} H_{4}$

$C_{3} H_{6}$

$C_{3} H_{3}$

$C_{3} H_{4}$

The successive members of a homologous series differ by $a C H_{2}$ group or by $12 + 2 \times 1 = 14$ mass unit. Hence, the homologue of $H C \equiv C H$ (ethyne, $C_{2} H_{2})$ is $C H_{3} - C \equiv C H$ (propyne, $C_{3} H_{4}$ ).