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Q.
The homologue of ethyne is
MGIMS WardhaMGIMS Wardha 2010
Solution:
The successive members of a homologous series differ by $ aC{{H}_{2}} $ group or by $ 12+2\times 1=14 $ mass unit. Hence, the homologue of $ HC\equiv CH $ (ethyne, $ {{C}_{2}}{{H}_{2}}) $ is $ C{{H}_{3}}-C\equiv CH $ (propyne, $ {{C}_{3}}{{H}_{4}} $ ).