The heat required for melting of sodium chloride is 30 kJ mol- 1. The entropy increase is 28.2 J mol- 1K- 1. The melting point of NaCl is: (Approximate your answer to nearest integer)

Question

The heat required for melting of sodium chloride is 30 kJ mol- 1. The entropy increase is 28.2 J mol- 1K- 1. The melting point of NaCl is: (Approximate your answer to nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ S=(Δ H textfusion /T) Where, T is melting point. T=(Δ H textfusion /Δ S)=(30300 J mol- 1/28 . 2) =1075.23 K

Q. The heat required for melting of sodium chloride is $30 k J m o l^{- 1} .$ The entropy increase is $28.2 J m o l^{- 1} K^{- 1} .$ The melting
point of $N a Cl$ is:
(Approximate your answer to nearest integer)

$Δ S = \frac{Δ H _{fusion}}{T}$
Where, $T$ is melting
point.
$T = \frac{Δ H _{fusion}}{Δ S} = \frac{30300 J m o l ^{- 1}}{28.2}$
$= 1075.23 K$

Q. The heat required for melting of sodium chloride is 30kJmol−1. The entropy increase is 28.2Jmol−1K−1. The melting point of NaCl is: (Approximate your answer to nearest integer)

ΔS=TΔHfusion ​​ Where, T is melting point. T=ΔSΔHfusion ​​=28.230300Jmol−1​ =1075.23K

Q. The heat required for melting of sodium chloride is $30 k J m o l^{- 1} .$ The entropy increase is $28.2 J m o l^{- 1} K^{- 1} .$ The melting
point of $N a Cl$ is:
(Approximate your answer to nearest integer)

$Δ S = \frac{Δ H _{fusion}}{T}$
Where, $T$ is melting
point.
$T = \frac{Δ H _{fusion}}{Δ S} = \frac{30300 J m o l ^{- 1}}{28.2}$
$= 1075.23 K$