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Q. The heat required for melting of sodium chloride is $30\,kJ\,mol^{- 1}.$ The entropy increase is $28.2\,J\,mol^{- 1}K^{- 1}.$ The melting
point of $NaCl$ is:
(Approximate your answer to nearest integer)

NTA AbhyasNTA Abhyas 2022

Solution:

$\Delta S=\frac{\Delta H_{\text{fusion }}}{T}$
Where, $T$ is melting
point.
$T=\frac{\Delta H_{\text{fusion }}}{\Delta S}=\frac{30300 \,J \,mol^{- 1}}{28 . 2}$
$=1075.23\,K$