The HCF of (x-1)(x2-4) and (x2-1)(x+2) is

Question

The HCF of (x-1)(x2-4) and (x2-1)(x+2) is (A) x-2 (B) x+1 (C) x-1 (D) (x-1)(x+2)

Tardigrade Admin · Accepted Answer

(i) HCF is the product of the common factors with least exponents. (ii) Factorize the given expressions by using a2-b2= (a+b)(a-b). (iii) HCF is the product of common factors with least exponents.

Q. The HCF of $(x - 1) (x^{2} - 4)$ and $(x^{2} - 1) (x + 2)$ is

$x - 2$

$x + 1$

$x - 1$

$(x - 1) (x + 2)$

(i) HCF is the product of the common factors with least exponents.
(ii) Factorize the given expressions by using $a^{2} - b^{2} =$ $(a + b) (a - b)$ .
(iii) $H CF$ is the product of common factors with least exponents.

Q. The HCF of (x−1)(x2−4) and (x2−1)(x+2) is

x−2

x+1

x−1

(x−1)(x+2)