1. Tardigrade
  2. Question
  3. Mathematics
  4. The HCF of (x-1)(x2-4) and (x2-1)(x+2) is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The HCF of $(x-1)\left(x^2-4\right)$ and $\left(x^2-1\right)(x+2)$ is

Polynomials, LCM and HCF of Polynomials

Solution:

(i) HCF is the product of the common factors with least exponents.
(ii) Factorize the given expressions by using $a^2-b^2=$ $(a+b)(a-b)$.
(iii) $HCF$ is the product of common factors with least exponents.