The half life period for catalytic decomposition of AB3 at 50 mm is found to be 4 hrs and at 100 mm it is 2.0 hrs. The order of reaction is

Question

The half life period for catalytic decomposition of AB3 at 50 mm is found to be 4 hrs and at 100 mm it is 2.0 hrs. The order of reaction is (A) 3 (B) 1 (C) 2 (D) 0

Tardigrade Admin · Accepted Answer

t1/2 propto (1/(P)n-1) where n is orde Now ((t1/2)1/(t1/2)2)=((p2/p1))n-1 or (2/4)=((50/100))n-1 or(1/2)= (1/2)=((1/2))n-1 or n-1 =1 or n=2

Q. The half life period for catalytic decomposition of $A B_{3}$ at 50 mm is found to be 4 hrs and at 100 mm it is 2.0 hrs. The order of reaction is

3

1

2

0

$t_{1/2} \propto \frac{1}{( P ) ^{n - 1}}$ where n is orde
$N o w \frac{( t _{1/2} ) _{1}}{( t _{1/2} ) _{2}} = (\frac{p _{2}}{p _{1}})^{n - 1}$
$or \frac{2}{4} = (\frac{50}{100})^{n - 1}$
or $\frac{1}{2} = \frac{1}{2} = (\frac{1}{2})^{n - 1}$ or n-1 =1 or n=2

Q. The half life period for catalytic decomposition of AB3​ at 50 mm is found to be 4 hrs and at 100 mm it is 2.0 hrs. The order of reaction is

3

1

2

0

t1/2​∝(P)n−11​ where n is orde Now(t1/2​)2​(t1/2​)1​​=(p1​p2​​)n−1 or42​=(10050​)n−1 or21​=21​=(21​)n−1 or n-1 =1 or n=2

Q. The half life period for catalytic decomposition of $A B_{3}$ at 50 mm is found to be 4 hrs and at 100 mm it is 2.0 hrs. The order of reaction is

$t_{1/2} \propto \frac{1}{( P ) ^{n - 1}}$ where n is orde
$N o w \frac{( t _{1/2} ) _{1}}{( t _{1/2} ) _{2}} = (\frac{p _{2}}{p _{1}})^{n - 1}$
$or \frac{2}{4} = (\frac{50}{100})^{n - 1}$
or $\frac{1}{2} = \frac{1}{2} = (\frac{1}{2})^{n - 1}$ or n-1 =1 or n=2