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Q.
The half life period for catalytic decomposition of $AB_3$ at 50 mm is found to be 4 hrs and at 100 mm it is 2.0 hrs. The order of reaction is
Chemical Kinetics
Solution:
$t_{1/2} \propto \frac{1}{(P)^{n-1}}$ where n is orde
$Now \, \frac{(t_{1/2})_1}{(t_{1/2})_2}=\left(\frac{p_2}{p_1}\right)^{n-1}$
$or \frac{2}{4}=\left(\frac{50}{100}\right)^{n-1}$
or$\frac{1}{2}= \frac{1}{2}=\left(\frac{1}{2}\right)^{n-1} $ or n-1 =1 or n=2