The ground state energy of hydrogen atom is -13.6 eV. The kinetic energy of the electron in this state is

Question

The ground state energy of hydrogen atom is -13.6 eV. The kinetic energy of the electron in this state is (A) 2.18× 10-14 J (B) 2.18× 10-16 J (C) 2.18× 10-18 J (D) 2.18× 10-19 J

Tardigrade Admin · Accepted Answer

Here the ground state energy, (E) = -13.6 eV Since, K.E. of the electron = - E = 13.6 eV = 13.6 × 1.6 × 10-19 J = 21.76 × 10-19 J = 2.18 × 10-18 J

Q. The ground state energy of hydrogen atom is $- 13.6 e V$ . The kinetic energy of the electron in this state is

$2.18 \times 1 0^{- 14} J$

$2.18 \times 1 0^{- 16} J$

$2.18 \times 1 0^{- 18} J$

$2.18 \times 1 0^{- 19} J$

Here the ground state energy, $(E) = - 13.6 e V$
Since, K.E. of the electron $= - E = 13.6 e V$
$= 13.6 \times 1.6 \times 1 0^{- 19} J$
$= 21.76 \times 1 0^{- 19} J$
$= 2.18 \times 1 0^{- 18} J$

Q. The ground state energy of hydrogen atom is −13.6eV. The kinetic energy of the electron in this state is

2.18×10−14J

2.18×10−16J

2.18×10−18J

2.18×10−19J