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Physics
The ground state energy of hydrogen atom is -13.6 eV. The kinetic energy of the electron in this state is
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Q. The ground state energy of hydrogen atom is $-13.6 \,eV$. The kinetic energy of the electron in this state is
Atoms
A
$2.18\times 10^{-14}\,J$
24%
B
$2.18\times 10^{-16}\,J$
24%
C
$2.18\times 10^{-18}\,J$
35%
D
$2.18\times 10^{-19}\,J$
18%
Solution:
Here the ground state energy, $(E) = -13.6 \,eV$
Since, K.E. of the electron $= - E = 13.6 \,eV$
$= 13.6 \times 1.6 \times 10^{-19}\, J$
$ = 21.76 \times 10^{-19}\, J$
$ = 2.18 \times 10^{-18}\, J$