The ground state electronic configuration of valence shell electrons in nitrogen molecule ( N 2) is written as K K, σ 2 s2, overset*σ 2 s2, σ 2 px2, π 2 py2 ≈ π 2 pz2 Bond order in nitrogen molecule is

Question

The ground state electronic configuration of valence shell electrons in nitrogen molecule ( N 2) is written as K K, σ 2 s2, overset*σ 2 s2, σ 2 px2, π 2 py2 ≈ π 2 pz2 Bond order in nitrogen molecule is (A) 0 (B) 1 (C) 2 (D) 3

Tardigrade Admin · Accepted Answer

The MO configuration of N 2 is K K, σ 2 s2, overset* σ 2 s2, σ 2 px2, π 2 py2 ≈ π 2 pz2 Bond order of N2=(1/2)[Nb-Na]=(1/2)[8-2]=(6/2)=3

Q. The ground state electronic configuration of valence shell electrons in nitrogen molecule $(N_{2})$ is written as
$KK, σ 2 s^{2}, σ * 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2} \approx π 2 p_{z}^{2}$
Bond order in nitrogen molecule is

0

1

2

3

The $MO$ configuration of $N_{2}$ is
$KK, σ 2 s^{2}, σ * 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2} \approx π 2 p_{z}^{2}$
Bond order of
$N_{2} = \frac{1}{2} [N_{b} - N_{a}] = \frac{1}{2} [8 - 2] = \frac{6}{2} = 3$

Q. The ground state electronic configuration of valence shell electrons in nitrogen molecule (N2​) is written as KK,σ2s2,σ∗2s2,σ2px2​,π2py2​≈π2pz2​ Bond order in nitrogen molecule is

0

1

2

3

The MO configuration of N2​ is KK,σ2s2,σ∗2s2,σ2px2​,π2py2​≈π2pz2​ Bond order of N2​=21​[Nb​−Na​]=21​[8−2]=26​=3

Q. The ground state electronic configuration of valence shell electrons in nitrogen molecule $(N_{2})$ is written as
$KK, σ 2 s^{2}, σ * 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2} \approx π 2 p_{z}^{2}$
Bond order in nitrogen molecule is

The $MO$ configuration of $N_{2}$ is
$KK, σ 2 s^{2}, σ * 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2} \approx π 2 p_{z}^{2}$
Bond order of
$N_{2} = \frac{1}{2} [N_{b} - N_{a}] = \frac{1}{2} [8 - 2] = \frac{6}{2} = 3$