The graph of an object’s motion (along the x-axis) is shown in the figure. The instantaneous velocity of the object at points A and B are vA and vB respectively. Then

Question

The graph of an object’s motion (along the x-axis) is shown in the figure. The instantaneous velocity of the object at points A and B are vA and vB respectively. Then (A) vA = vB = 0.5 m/s  (B) vA = 0 .5 m/s < vB (C) vA = 0 .5 m/s > vB (D) vA = vB = 2 m/s

Tardigrade Admin · Accepted Answer

Instantaneous velocity v=(Δ xA/Δ tA)=(4m/8s)=0.5 m/s and vB=(Δ xB/Δ tB)=(8m/16s)=0.5 m/s i.e., vA=vB=0.5 m/s

Q. The graph of an object’s motion (along the x-axis) is shown in the figure. The instantaneous velocity of the object at points $A$ and $B$ are $v_{A}$ and $v_{B}$ respectively. Then

$v_{A} = v_{B} = 0.5 m / s$

$v_{A} = 0.5 m / s < v_{B}$

$v_{A} = 0.5 m / s > v_{B}$

$v_{A} = v_{B} = 2 m / s$

Instantaneous velocity $v = \frac{Δ x _{A}}{Δ t _{A}} = \frac{4 m}{8 s} = 0.5 m / s$
and $v_{B} = \frac{Δ x _{B}}{Δ t _{B}} = \frac{8 m}{16 s} = 0.5 m / s$
i.e., $v_{A} = v_{B} = 0.5 m / s$

Q. The graph of an object’s motion (along the x-axis) is shown in the figure. The instantaneous velocity of the object at points A and B are vA​ and vB​ respectively. Then

vA​=vB​=0.5m/s

vA​=0.5m/s<vB​

vA​=0.5m/s>vB​

vA​=vB​=2m/s