Question

The geometry of the compound $\left[Pt{\left(N{H}_3\right)}_{2}C{l}_2\right]$ is

• A. square planar
• B. pyramidal
• C. tetrahedral
• D. octahedral.

Answer 1

Answer: (A)

Oxidation state of $Pt$ in $\left[Pt{\left(N{H}_3\right)}_{2}C{l}_2\right]=+2$
$P{t}^{2+}\to 4d^8$
Ligand $N{H}_3$ forces the d-electrons to pair up.
$\left[Pt{\left(N{H}_3\right)}_{2}C{l}_2\right]\to$
$ds{p}^2$ hybridisation leads to square planar geometry