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Q.
The geometry of the compound $\left[Pt\left(NH_{3}\right)_{2}Cl_{2}\right]$ is
Coordination Compounds
Solution:
Oxidation state of $Pt$ in $\left[Pt\left(NH_{3}\right)_{2}Cl_{2}\right]= + 2$
$Pt^{2+} \to 4d^{8}$
Ligand $NH_{3}$ forces the d-electrons to pair up.
$\left[Pt\left(NH_{3}\right)_{2}Cl_{2}\right] \to$
$dsp^{2}$ hybridisation leads to square planar geometry
