The geometry of Ni(CO)4 and Ni(PPh3)Cl2 are:

Question

The geometry of Ni(CO)4 and Ni(PPh3)Cl2 are: (A) both square planar (B) tetrahedral and square planar respectively (C) both tetrahedral (D) square planar and tetrahedral respectively

Tardigrade Admin · Accepted Answer

Ni(CO)4- Oxidation state of Ni=0 . Oxidation state of Ni in Ni(PPh3)2Cl2 is x+0× 2+(-2)=0 ∴ x=+2

Q. The geometry of $N i (CO)_{4}$ and $N i (PP h_{3}) C l_{2}$ are:

both square planar

tetrahedral and square planar respectively

both tetrahedral

square planar and tetrahedral respectively

$N i (CO)_{4} -$ Oxidation state of $N i = 0$ .
Oxidation state of $N i$ in $N i (PP h_{3})_{2} C l_{2}$
is $x + 0 \times 2 + (- 2) = 0$ $∴$ $x = + 2$

Q. The geometry of Ni(CO)4​ and Ni(PPh3​)Cl2​ are: