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  4. The geometry of Ni(CO)4 and Ni(PPh3)Cl2 are:

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Q. The geometry of $ Ni{{(CO)}_{4}} $ and $ Ni(PP{{h}_{3}})C{{l}_{2}} $ are:

BHUBHU 2005

Solution:

$ Ni{{(CO)}_{4}}- $ Oxidation state of $ Ni=0 $ .
Oxidation state of $ Ni $ in $ Ni{{(PP{{h}_{3}})}_{2}}C{{l}_{2}} $
is $ x+0\times 2+(-2)=0 $ $ \therefore $ $ x=+2 $

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