Question

The geometry of electron pairs around $I$ in $I{F}_5$ is:

• A. Octahedral
• B. Trigonal Bipyramidal
• C. Square Pyramidal
• D. Pentagonal Planar

Answer 1

Answer: (C)

$I{F}_5=.7+5\times 7=\frac{42}{8}=5+1$

$s{p}^3{d}^2$ hybridisation, hence it should be octahedral.

Due to the presence of one lone pair of electrons, its actual geometry is square pyramidal.