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  4. The geometry of electron pairs around I in IF 5 is:

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Q. The geometry of electron pairs around $ I $ in $IF _{5}$ is:

Chemical Bonding and Molecular Structure

Solution:

$IF _{5}=.7+5 \times 7=\frac{42}{8}=5+1$

$sp ^{3} d ^{2}$ hybridisation, hence it should be octahedral.

Due to the presence of one lone pair of electrons, its actual geometry is square pyramidal.

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