The geometry of [Cu(NH3)4]2+ ion is:

Question

The geometry of [Cu(NH3)4]2+ ion is: (A) trigonal bipyramidal (B) tetrahedral (C) octahedral (D) square planar

Tardigrade Admin · Accepted Answer

29Cu=1s2,2s22p6,3s23p63d10,4s1 Cu2+=[Ar] 3d9,4s04p0 Hence, geometry of [Cu(NH3)4]2+ ion is square-planar and it is paramagnetic ion, as it has one unpaired electron.

Q. The geometry of $[C u (N H_{3})_{4}]^{2 +}$ ion is:

trigonal bipyramidal

tetrahedral

octahedral

square planar

$_{29} C u = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{10}, 4 s^{1}$ $C u^{2 +} = [A r] 3 d^{9}, 4 s^{0} 4 p^{0}$
Hence, geometry of $[C u (N H_{3})_{4}]^{2 +}$ ion is square-planar and it is paramagnetic ion, as it has one unpaired electron.

Q. The geometry of [Cu(NH3​)4​]2+ ion is: