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  4. The geometry of [Cu(NH3)4]2+ ion is:

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Q. The geometry of $ {{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}} $ ion is:

JIPMERJIPMER 1998

Solution:

$ {}_{29}Cu=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},4{{s}^{1}} $ $ C{{u}^{2+}}=[Ar]\,3{{d}^{9}},4{{s}^{0}}4{{p}^{0}} $
Hence, geometry of $ {{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}} $ ion is square-planar and it is paramagnetic ion, as it has one unpaired electron.

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