The geometry around boron in the product 'B' formed from the following reaction is BF 3+ NaH xrightarrow450 K A + NaF A + NMe 3 arrow B

Question

The geometry around boron in the product 'B' formed from the following reaction is BF 3+ NaH xrightarrow450 K A + NaF A + NMe 3 arrow B (A) trigonal planar (B) tetrahedral (C) pyramidal (D) square planar

Tardigrade Admin · Accepted Answer

BF3 + NaH xrightarrow450 K underset text(diborane)B2H6 + NaF B2H6 + NMe3 arrow underset textsymmetrical cleavage2[BH3 arrow NMe3]

Q. The geometry around boron in the product 'B' formed from the following reaction is
$B F_{3} + N a H 450 K A + N a F$
$A + NM e_{3} \to B$

trigonal planar

tetrahedral

pyramidal

square planar

$B F_{3} + N a H 450 K (diborane) B_{2} H_{6} + N a F$
$B_{2} H_{6} + NM e_{3} \to symmetrical cleavage 2 [B H_{3} \leftarrow NM e_{3}]$

Q. The geometry around boron in the product 'B' formed from the following reaction is BF3​+NaH450K​A+NaF A+NMe3​→B