Question

The geometry and magnetic property of $[NiC{l}_4{]}^{2-}$, respectively are

• A. tetrahedral, paramagnetic
• B. tetrahedral, diamagnetic
• C. square planar, paramagnetic
• D. square planar, diamagnetic

Answer 1

Answer: (A)

The oxidation state of $Ni$ in $[NiC{l}_4{]}^{2-}$ is $+2$. The electronic configuration of $N{i}^{2+}$ is $[Ar]3d^{8}4s^0$

As $C{l}^{-}$ is a weak field ligand, pairing of electron will not occur.

As the hybridisation of $Ni$ in $[NiC{l}_4{]}^{2-}$ is $s{p}^3$. Thus, the geometry will be tetrahedral. It is paramagnetic in nature as there are $2$ unpaired electrons.