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Q. The geometry and magnetic property of $[NiCl_4]^{2-}$, respectively are

KVPYKVPY 2017Coordination Compounds

Solution:

The oxidation state of $Ni$ in $[NiCl_4]^{2-}$ is $+2$. The electronic configuration of $Ni^{2+}$ is $[Ar]3d^8 4s^0$
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As $Cl^-$ is a weak field ligand, pairing of electron will not occur.
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As the hybridisation of $Ni$ in $[NiCl_4]^{2-}$ is $sp^3$. Thus, the geometry will be tetrahedral. It is paramagnetic in nature as there are $2$ unpaired electrons.