Question

The general solutions of the following equation : $\tan 2\theta =0$ is

• A. $\theta =\frac{n}{2}+\pi ,n\in Z$
• B. $\theta =\frac{n\pi }{2},n\in Z$
• C. $\theta =\frac{\pi }{2}+n,n\in Z$
• D. None

Answer 1

Answer: (B)

We know that the general solution of the equation
$\tan \theta =0$ is $\theta =n\pi ,n\in Z$. Therefore,
$\tan 2\theta =0\Rightarrow 2\theta =n\pi ,n\in Z$
$\Rightarrow \theta =\frac{n\pi }{2},n\in Z$