Question

The general solutions of the following equation : $\tan \, 2\theta = 0$ is

• A. $\theta = \frac{n}{2} + \pi , n \in Z $
• B. $\theta = \frac{n\pi }{2} , n \in Z $
• C. $\theta = \frac{\pi}{2} + n , n \in Z $
• D. None

Answer 1

Answer: (B)

We know that the general solution of the equation
$\tan \, \theta = 0 $ is $\theta = n \pi , n \in Z$. Therefore,
$\tan \, 2 \theta = 0 \, \Rightarrow \, 2 \theta = n \pi , n \in Z$
$ \Rightarrow \, \, \theta = \frac{ n \pi}{2} , n \in Z $