Question

The general solution of the equation $\sin x+\cos x=2$ is

• A. $x=n\pi +(-1{)}^n\frac{\pi }{4},n=.....-3,-2,-1,0,1,2,3,..$
• B. $x=n\pi +(-1{)}^n\frac{\pi }{6},n.......,-3,-2,-1,0,1,2,3,......$
• C. $x=n\pi +(-1{)}^{n+1}\frac{\pi }{4},n=.......-3,-2,-1,0,1,2,3,.....$
• D. Does not exist.

Answer 1

Answer: (D)

$\sin x+\cos x=2$ , no solution is possible.
[$\because$ value of $\sin x+\cos x$ is always less than 2]