Question

The general solution of the equation $\sin x + \cos x = 2$ is

• A. $ x = n\pi +(-1)^n\frac{\pi}{4},n=..... -3,-2, - 1,0, 1,2, 3, ..$
• B. $ x=n\pi+(-1)^n\frac{\pi}{6},n.......,-3,-2,-1,0,1,2,3,......$
• C. $x=n\pi+(-1)^{n+1}\frac{\pi}{4},n=.......-3,-2,-1,0,1,2,3,.....$
• D. Does not exist.

Answer 1

Answer: (D)

$\sin x + \cos x = 2$ , no solution is possible.
[$\because$ value of $\sin x + \cos x$ is always less than 2]