The frequency of a tuning fork is 384 m/s and velocity of sound in air is 352 m/s. Find how far the sound has traversed while fork completes 36 vibrations.

Question

The frequency of a tuning fork is 384 m/s and velocity of sound in air is 352 m/s. Find how far the sound has traversed while fork completes 36 vibrations. (A) 33 m (B) 16.5 m (C) 11 m (D) 22 m

Tardigrade Admin · Accepted Answer

The distance moved by the wave in the time of one complete oscillation of a particle of the medium is called the wavelength

(X)

.
Also

λ = \frac{velocity (v)}{frequency (n)}

Given,

n = 384/ s, v = 352 m / s

Distance moved in

36

vibrations is

λ = \frac{36 \times 352}{384} = 33 m

.

Q. The frequency of a tuning fork is 384m/s and velocity of sound in air is 352m/s. Find how far the sound has traversed while fork completes 36 vibrations.

33 m

16.5 m

11 m

22 m

The distance moved by the wave in the time of one complete oscillation of a particle of the medium is called the wavelength (X). Also λ=frequency (n)velocity (v)​ Given, n=384/s,v=352m/s Distance moved in 36 vibrations is λ=38436×352​=33m.

Q. The frequency of a tuning fork is $384 m / s$ and velocity of sound in air is $352 m / s$ . Find how far the sound has traversed while fork completes $36$ vibrations.

The distance moved by the wave in the time of one complete oscillation of a particle of the medium is called the wavelength $(X)$ .
Also $λ = \frac{velocity (v)}{frequency (n)}$
Given, $n = 384/ s, v = 352 m / s$
Distance moved in $36$ vibrations is
$λ = \frac{36 \times 352}{384} = 33 m$ .