The forbidden energy gap in Ge is 0.72 eV. Given, hc = 12400 eV - mathringA . The maximum wavelength of radiation that will generate an electron hole pair is

Question

The forbidden energy gap in Ge is 0.72 eV. Given, hc = 12400 eV - mathringA . The maximum wavelength of radiation that will generate an electron hole pair is (A) 17222 mathringA (B) 1722 mathringA (C) 172220 mathringA (D) 172.2 mathringA

Tardigrade Admin · Accepted Answer

Energy gap, Eg=(h c/λ) λ=(h c/Eg)=(12400/0.72)=17222 mathringA

Q. The forbidden energy gap in $G e$ is $0.72 e V$ . Given, $h c = 12400 e V - \overset{˚}{A}$ . The maximum wavelength of radiation that will generate an electron hole pair is

$17222 \overset{˚}{A}$

$1722 \overset{˚}{A}$

$172220 \overset{˚}{A}$

$172.2 \overset{˚}{A}$

Energy gap, $E_{g} = \frac{h c}{λ}$
$λ = \frac{h c}{E _{g}} = \frac{12400}{0.72} = 17222 \overset{˚}{A}$

Q. The forbidden energy gap in Ge is 0.72eV. Given, hc=12400eV−A˚ . The maximum wavelength of radiation that will generate an electron hole pair is

17222A˚

1722A˚

172220A˚

172.2A˚