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  4. The forbidden energy gap in Ge is 0.72 eV. Given, hc = 12400 eV - mathringA . The maximum wavelength of radiation that will generate an electron hole pair is

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Q. The forbidden energy gap in $Ge$ is $0.72\, eV$. Given, $hc = 12400 \, eV \, - \mathring{A}$ . The maximum wavelength of radiation that will generate an electron hole pair is

KCETKCET 2010Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Energy gap, $E_{g}=\frac{h c}{\lambda}$
$\lambda=\frac{h c}{E_{g}}=\frac{12400}{0.72}=17222\, \mathring{A}$