Question

The following graph represents the variation of photo current with anode potential for a metal surface. Here $I_1$, $I_2$ and $I_3$ represents intensities and ${\gamma }_1$, ${\gamma }_2$, ${\gamma }_3$ represent frequency for curves $1,2$ and $3$ respectively, then

• A. ${\gamma }_1={\gamma }_2$ and $I_1\ne I_2$
• B. ${\gamma }_1={\gamma }_3$ and $I_1\ne I_3$
• C. ${\gamma }_1={\gamma }_2$ and $I_1=I_2$
• D. ${\gamma }_2={\gamma }_3$ and $I_1=I_3$

Answer 1

Answer: (A)

Here in the graph we can see that, the Stopping potential is same for $1$ and $2$ . So, frequencies will be same i.e. ${\gamma }_1={\gamma }_2$ and, currents are different. So, intensity are different i.e. $I_1\ne I_2$.