Question

The following graph represents the variation of photo current with anode potential for a metal surface. Here $I_1$, $I_2$ and $I_3$ represents intensities and $\gamma_1$, $\gamma_2$, $\gamma_3$ represent frequency for curves $1, 2$ and $3$ respectively, then

• A. $\gamma_1 = \gamma_2$ and $I_1 \ne I_2$
• B. $\gamma_1 = \gamma_3$ and $I_1 \ne I_3$
• C. $\gamma_1 = \gamma_2$ and $I_1 = I_2$
• D. $\gamma_2 = \gamma_3$ and $I_1 = I_3$

Answer 1

Answer: (A)

Here in the graph we can see that, the Stopping potential is same for $1$ and $2$ . So, frequencies will be same i.e. $\gamma _{1}= \gamma _{2}$ and, currents are different. So, intensity are different i.e. $I_{1} \neq I_{2}$.