The flocculation value of HCl for arsenic sulphide sol. is 30 m mol L- 1 . If H2SO4 is used for the flocculation of arsenic sulphide, the amount, in grams of H2SO4 in 250 ml required for the above purposed is y× 10- 2g . Calculate value of y? (molecular mass of H2SO4=98 g/mol )

Question

The flocculation value of HCl for arsenic sulphide sol. is 30 m mol L- 1 . If H2SO4 is used for the flocculation of arsenic sulphide, the amount, in grams of H2SO4 in 250 ml required for the above purposed is y× 10- 2g . Calculate value of y? (molecular mass of H2SO4=98 g/mol ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

m . moles of HC required for 1 lit.=30 m . moles of H2SO41 lit.=15 m . moles of H2SO4 in 250 ml=(15/4) weight of H2SO4=(15/4)× 10- 3× 98 =0.37 gm

Q. The flocculation value of HCl for arsenic sulphide sol. is 30mmolL−1 . If H2​SO4​ is used for the flocculation of arsenic sulphide, the amount, in grams of H2​SO4​ in 250ml required for the above purposed is y×10−2g . Calculate value of y? (molecular mass of H2​SO4​=98g/mol )

m . moles of HC required for 1lit.=30 m . moles of H2​SO4​1lit.=15 m . moles of H2​SO4​ in 250ml=415​ weight of H2​SO4​=415​×10−3×98 =0.37gm

$m$ . moles of $H C$ required for $1 l i t . = 30$
$m$ . moles of $H_{2} S O_{4} 1 l i t . = 15$
$m$ . moles of $H_{2} S O_{4}$ in $250 m l = \frac{15}{4}$
weight of $H_{2} S O_{4} = \frac{15}{4} \times 1 0^{- 3} \times 98$
$= 0.37 g m$