Question

The first-order rate constant k is related to temperature as log $k=15.0-\left(10^6/T\right).$ Which of the following pair of value is correct?

• A. $A=10^{15}$ and $E=1.9\times 10^{4}kJ$
• B. $A=10^{-15}$ and $E=40kJ$
• C. $A=l{0}^{-15}$ and $E=40kJ$
• D. $A=10^{-15}$ and $E=1.9\times 10^{4}kJ$

Answer 1

Answer: (A)

log $k=15.0-\frac{10^6}{T}$
log $k$= log $A-\frac{E}{2.303R}$
we find $A=10^{15}E=1.9\times 10^{4}J$