Question

The first-order rate constant k is related to temperature as log $k = 15.0 - \left(10^6 /T\right).$ Which of the following pair of value is correct?

• A. $A = 10^{15}$ and $E = 1.9 \times 10^4 kJ$
• B. $A = 10^{-15}$ and $E = 40 kJ$
• C. $A =l0^{-15}$ and $E = 40 kJ$
• D. $A = 10^{-15}$ and $E = 1.9 \times 10^4 kJ$

Answer 1

Answer: (A)

log $k = 15.0-\frac{10^{6}}{T}$
log $k$= log $A-\frac{E}{2.303R}$
we find $A=10^{15} E=1.9\times10^{4}J$