The first ionization energy of H is 21.79 × 10-19 J. Determine the second ionization energy of He atom. Give your answer as multiple of 10-19.

Question

The first ionization energy of H is 21.79 × 10-19 J. Determine the second ionization energy of He atom. Give your answer as multiple of 10-19. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

I.P. =13.6 × (Z2/n2)= IP of H × (Z2/n2) He =21.79 × 10-19 × (Z2/12) =87.16 × 10-19 Joule

Q. The first ionization energy of $H$ is $21.79 \times 1 0^{- 19} J$ . Determine the second ionization energy of $He$ atom. Give your answer as multiple of $1 0^{- 19}$ .

$I . P . = 13.6 \times \frac{Z ^{2}}{n ^{2}} =$ $I P$ of $H \times \frac{Z ^{2}}{n ^{2}}$
$He = 21.79 \times 1 0^{- 19} \times \frac{Z ^{2}}{1 ^{2}}$
$= 87.16 \times 1 0^{- 19}$ Joule

Q. The first ionization energy of H is 21.79×10−19J. Determine the second ionization energy of He atom. Give your answer as multiple of 10−19.

I.P.=13.6×n2Z2​= IP of H×n2Z2​ He=21.79×10−19×12Z2​ =87.16×10−19 Joule

Q. The first ionization energy of $H$ is $21.79 \times 1 0^{- 19} J$ . Determine the second ionization energy of $He$ atom. Give your answer as multiple of $1 0^{- 19}$ .

$I . P . = 13.6 \times \frac{Z ^{2}}{n ^{2}} =$ $I P$ of $H \times \frac{Z ^{2}}{n ^{2}}$
$He = 21.79 \times 1 0^{- 19} \times \frac{Z ^{2}}{1 ^{2}}$
$= 87.16 \times 1 0^{- 19}$ Joule