1. Tardigrade
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  3. Chemistry
  4. The first ionization energy of H is 21.79 × 10-19 J. Determine the second ionization energy of He atom. Give your answer as multiple of 10-19.

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Q. The first ionization energy of $H$ is $21.79 \times 10^{-19} \,J$. Determine the second ionization energy of $He$ atom. Give your answer as multiple of $10^{-19}$.

Structure of Atom

Solution:

$I.P. =13.6 \times \frac{Z^{2}}{n^{2}}=$ $IP$ of $ H \times \frac{Z^{2}}{n^{2}}$
$He =21.79 \times 10^{-19} \times \frac{Z^{2}}{1^{2}} $
$=87.16 \times 10^{-19}$ Joule