The first diffraction minimum due to single slit diffraction is formed at θ, for light of wave length 5000 A, if the width of slit is 1 × 10-4, then the value of θ is

Question

The first diffraction minimum due to single slit diffraction is formed at θ, for light of wave length 5000 A, if the width of slit is 1 × 10-4, then the value of θ is (A) 30° (B) 45° (C) 60° (D) 15°

Tardigrade Admin · Accepted Answer

a sin θ=n λ ⇒ 1 × 10-4 × 10-2 sin θ=1 × 5 × 10-7 ⇒ sin θ=0.5 θ=30°

Q. The first diffraction minimum due to single slit diffraction is formed at $θ$ , for light of wave length $5000 A$ , if the width of slit is $1 \times 1 0^{- 4}$ , then the value of $θ$ is

$3 0^{\circ}$

$4 5^{\circ}$

$6 0^{\circ}$

$1 5^{\circ}$

$a sin θ = nλ$
$\Rightarrow 1 \times 1 0^{- 4} \times 1 0^{- 2} sin θ = 1 \times 5 \times 1 0^{- 7}$
$\Rightarrow sin θ = 0.5$
$θ = 3 0^{\circ}$

Q. The first diffraction minimum due to single slit diffraction is formed at θ, for light of wave length 5000A, if the width of slit is 1×10−4, then the value of θ is

30∘

45∘

60∘

15∘