The figure shows stopping potential Vs and frequency 0 for two different metallic surfaces A and B. The work function of A, as compared to that of B is

Question

The figure shows stopping potential Vs and frequency 0 for two different metallic surfaces A and B. The work function of A, as compared to that of B is (A) less (B) more (C) equal (D) nothing can be said

Tardigrade Admin · Accepted Answer

The value of threshold frequency v0 for A is less than that for B, hence φA < φB.

Q. The figure shows stopping potential $V_{s}$ and frequency 0 for two different metallic surfaces $A$ and $B$ . The work function of $A$ , as compared to that of $B$ is

less

more

equal

nothing can be said

The value of threshold frequency $v_{0}$ for $A$ is less than that for $B$ , hence $ϕ_{A} < ϕ_{B}$ .

Q. The figure shows stopping potential Vs​ and frequency 0 for two different metallic surfaces A and B. The work function of A, as compared to that of B is