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Q. The figure shows stopping potential $V_{s}$ and frequency 0 for two different metallic surfaces $A$ and $B$. The work function of $A$, as compared to that of $B$ isPhysics Question Image

Dual Nature of Radiation and Matter

Solution:

The value of threshold frequency $v_{0}$ for $A$ is less than that for $B$, hence $\phi_{A} < \phi_{B}$.