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Tardigrade
Question
Mathematics
The expression sin 27 ° cos 57 ° sin 87 ° simplifies to
Q. The expression
s
in
2
7
∘
cos
5
7
∘
s
in
8
7
∘
simplifies to
1938
195
NTA Abhyas
NTA Abhyas 2020
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A
4
s
in
9
∘
0%
B
4
cos
9
∘
100%
C
2
s
in
9
∘
0%
D
2
cos
9
∘
0%
Solution:
s
in
2
7
∘
cos
5
7
∘
s
in
(
9
0
∘
−
3
∘
)
=
2
1
s
in
2
7
∘
(
2
cos
5
7
∘
cos
3
∘
)
=
2
1
s
in
2
7
∘
(
cos
6
0
∘
+
cos
5
4
∘
)
=
2
1
s
in
2
7
∘
(
2
1
)
+
2
1
s
in
2
7
∘
s
in
3
6
∘
=
4
1
s
in
2
7
∘
+
4
1
(
2
s
in
2
7
∘
s
in
3
6
∘
)
=
4
1
s
in
2
7
∘
+
4
1
(
cos
9
∘
−
cos
6
3
∘
)
=
4
1
s
in
2
7
∘
+
4
1
cos
9
∘
−
4
1
s
in
2
7
∘
=
4
1
cos
9
∘