The escape velocity from the earth is approximately equal to 11km/s . Find the escape velocity from a planet having twice the radius, and same density as that of earth:

Question

The escape velocity from the earth is approximately equal to 11km/s . Find the escape velocity from a planet having twice the radius, and same density as that of earth: (A) 22km/s (B) 11km/s (C) 5.5km/s (D) 15.5km/s

Tardigrade Admin · Accepted Answer

v=√(2 G M/R)=√2 G (4/3) π R2 d v propto R√d v=2v0

Q. The escape velocity from the earth is approximately equal to $11 km / s$ . Find the escape velocity from a planet having twice the radius, and same density as that of earth:

$22 km / s$

$11 km / s$

$5.5 km / s$

$15.5 km / s$

$v = \frac{2 GM}{R} = 2 G \frac{4}{3} π R^{2} d$
$v \propto R d$
$v = 2 v_{0}$

Q. The escape velocity from the earth is approximately equal to 11km/s . Find the escape velocity from a planet having twice the radius, and same density as that of earth:

22km/s

11km/s

5.5km/s

15.5km/s