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  4. The escape velocity from the earth is approximately equal to 11km/s . Find the escape velocity from a planet having twice the radius, and same density as that of earth:

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Q. The escape velocity from the earth is approximately equal to $11km/s$ . Find the escape velocity from a planet having twice the radius, and same density as that of earth:

NTA AbhyasNTA Abhyas 2020

Solution:

$v=\sqrt{\frac{2 G M}{R}}=\sqrt{2 G \frac{4}{3} \pi R^{2} d}$
$v \, \propto \, R\sqrt{d}$
$v=2v_{0}$