The escape velocity from the earth is about 11 km s- 1 . The escape velocity from a planet having twice the radius and the same mean density as the earth is

Question

The escape velocity from the earth is about 11 km s- 1 . The escape velocity from a planet having twice the radius and the same mean density as the earth is (A) 22 kms- 1 (B) 11 kms- 1 (C) 5.5 kms- 1 (D) 15.5 kms- 1

Tardigrade Admin · Accepted Answer

v=√(2 GM/R)=√2 G (4/3) π R2 d v propto R√d v=2v0

Q. The escape velocity from the earth is about $11 km s^{- 1}$ . The escape velocity from a planet having twice the radius and the same mean density as the earth is

$22 km s^{- 1}$

$11 km s^{- 1}$

$5.5 km s^{- 1}$

$15.5 km s^{- 1}$

$v = \frac{2 GM}{R} = 2 G \frac{4}{3} π R^{2} d$
$v \propto R d$
$v = 2 v_{0}$

Q. The escape velocity from the earth is about 11kms−1 . The escape velocity from a planet having twice the radius and the same mean density as the earth is

22kms−1

11kms−1

5.5kms−1

15.5kms−1