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Q. The escape velocity from the earth is about $11 \, km \, s^{- 1}$ . The escape velocity from a planet having twice the radius and the same mean density as the earth is

NTA AbhyasNTA Abhyas 2022

Solution:

$v=\sqrt{\frac{2 GM}{R}}=\sqrt{2 G \frac{4}{3} \pi R^{2} d}$
$v \, \propto \, R\sqrt{d}$
$v=2v_{0}$